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hao123彩票
22选5投注技巧：连号和分组投注
2013-06-28 16:09:31 来源： 字号：
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问题反馈
连号和分组投注 变22选5为11选3
从22个待选号码中，开出5个号码是很容易形成连号的，如果再考虑复式金银奖另外开出的2个号码，就更容易出现连号。即便不出现连号，彩民们也可以选择连号，以求用一组连号的2个号码去围剿某1个奖号。
按1-2、3-4、5-6......21-22，或者2-3、4-5......20-21、22-01这种形式组配连号的话，22个号码共组成11组2连号，每三组2连号结合一次，即11选3。彩民可以算出165张包6个号码的复式，其中，因其可能性少，有9张复式是6连号，将其删除。另有90张复式是4连号，也可考虑删除。最后，剩下的6码复式为69张，投注资金为828元。如果，5个奖号中出现一组奇数开头的连号，就至少能够中4个号码。例如，如果开奖号码为08-10-13-14-22，那么，在69张6码复式中，07-08-13-14-21-22、09-10-13-14-21-22都中得4个号码。如果某期奖号出现2组连号，828元的投注，就能获中一等奖。
一般来说，如果你不是职业彩民或者不是特别有把握，就不能如此投注，而应采取每个6码复式，有选择性地删掉一个号码，变复式为单注，从而大大降低投注金额。
同列号投注 变22选5为10选4
每个号码都有其个位数，个位数相同的号码，姑且称之为同列号，如01、11、21是1的同列号，08、18是8的同列号，22个号码的同列号为10个，即0-9。从分析22选5的开奖号码得知，超过65%的时候，5个奖号中有2个号码的个位数是相同的，也就是说，5个奖号一般由4个同列号组成。这样，彩民们就可以将22选5降至10选4，从0-9中选择4个尾数即可。例如选择同列号2、6、7、0，其所包含的9个号码是02-12-22-06-16-07-17-10-20。
同列号1、2各有3个号码，3-0各有2个号码，所以，选择4个尾数最多可以包含10个号码，最少则包含8个号码。从10个同列号中任意选择4个组合，共有210种，其中，全部是奇数和全部是偶数的同列号组合有10种，全部为小数(1-5)或全部为大数(6-0)的同列号组合有10种，除此之外，4个同列号都是自然连号的情况有4种：3-4-5-6、4-5-6-7、5-6-7-8、0-1-2-3，此前六期每期开奖号码的同列号组合情况有6种。这30种组合很难出现，可大胆删除，所剩的同列号组合为180种。
这180种同列号组合情况，还可以细分，按奇偶状态可分为三种形态，即三奇一偶、二奇二偶、一奇三偶;按数字大小亦可分为三种形态，即三大一小、二大二小、一大三小。每种形态都包含不少的组合，如在所余的180种组合中，三奇一偶的组合有48种。彩民们可以根据一段时间内开奖号码的整体走势进行判断，判断奇数走强则选择三奇一偶的组合，判断小数字走强，则选择一大三小的组合，两者综合考虑，一般只有20余种组合符合要求。如果彩民全选每个组合内的所有号码，则投入不菲，可考虑结合重复号、冷热号适量删减部分组合。
分区投注 变22选5为三个区间，分区选号
22个号码可以分成01-07、08-15、16-22三个区间，列出数期开奖号码：02-05-10-15-16，02-06-12-17-20，02-07-09-14-16，08-10-13-14-22......按其区间分布，彩民们可以发现，奖号的基本分布是三区兼顾，每个区间一般不会超过2个号码，虽也有某区大热而其他区间出现空白的情况出现，但不是主流，可忽略。每个区间选择2个号码，组成6码复式，基本上可以覆盖奖号。如上面所列的4期号码，如果采取三个区间各选2个号码的组合，有3期可以中一等奖。
除了以上我们所分析的情况之外，彩民们还可以采取选号缩水的形式进行投注。例如，确定每个区间各4个号码共12个号码、确定某6个同列号所包含的13个号码等，采取出5保4的矩阵进行缩水投注，其投注费用不高，而中奖可能性却大大提高。
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