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hao123彩票
寻求35选7的最佳组合：4+3 组配选号
2011-07-01 00:00:00 来源： 字号：
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问题反馈
对弱势号码进行"选3"组合。对弱势号码进行"选3"，每3个号码结成一个组合。同强势号码一样，弱势号码的搭配可能也是8种情况：大-偶-热、大-偶-冷、小-偶-热、小-偶-冷、大-奇-热、大-奇-冷、小-奇-热、小-奇-冷。因为已经选择了其中一种作为强势号码的搭配，且弱势号码的搭配不可能与强势号码的搭配重叠，所以，任选一种搭配都有高于1/8的可能选中弱势号码。符合任何一种搭配定义的弱势号码都不超过9个号码，即便算作9个号码，9选3的组合也只有84种。
最后，用4+3的组配模式成注。用4个强势号码加3个弱势号码组成7个号码的单注。假如强势号码是9选4，弱势号码是9选3，将其全部组合，则可以得到126×84=10584个单注。一次性投注这么多单注可行性不强，需大量剔除其中的"愚蠢组合"。
4+3的实战运用
①求小奖的4+3组配模式
在实战运用上，4+3组配模式可以有很好的延伸，并不是简单地选择4个奇数加上3个偶数之类的组合，如果并不追求大奖，则可以完全忽略弱势号码，只选择强势号码，将中奖目标定位在中得4～6个号码的奖项上。例如，确定奇数走强，则将18个奇数确定为强势号码，首先进行18选4，选择大约50～100种自认为最合理的4码组合，然后再对这18个奇数进行18选3，也选择大约50～100种3码心水组合。在进行4+3的组合搭配时，4码组合和3码组合会出现不少号码重复的单注，对于这些单注可以抛弃，使最终形成的单注在100个左右。
②求大奖的4+3组配模式
假设某期开奖号码小数有4个，大数有3个，而我们刚好选择了4个小数+3个大数的模式，那么，可以将18个小数或大数各剔除8个，对小数进行10选4，大数进行10选3，形成的单注是210×120=25200个，可以剔除部分全奇全偶、五个以上号码连号的组合等，只要没有将开奖号码剔除掉，肯定有一注中得头奖，同时还有不少的单注中得4～6个号码。而如果采取复式来包这20个大小号码，则形成的单注是77520个。
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