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hao123彩票
东方6+1选号技巧：奇数最大连续数量选号
2008-08-05 00:00:00 来源： 字号：
T |
T |
T
问题反馈
根据奇数最大连续出数的情况，福彩”6+1”前区的号码分布情况如下：
奇数最大连续数量形态 | 号码数量 | 所占比例（%） | 理论周期 |
0奇 | 15625 | 1.5625 | 64 |
1奇 | 312500 | 31.25 | 3.2 |
2连奇 | 359375 | 35.9375 | 2.8 |
3连奇 | 187500 | 18.75 | 5.3 |
4连奇 | 78125 | 7.8125 | 12.8 |
5连奇 | 31250 | 3.125 | 32 |
6连奇 | 15625 | 1.5625 | 64 |
从上表中我们可以发现，奇数最大连续1次或者2次的号码，占总量的比例最大，分别为31%，36%，所以开奖号码中，两连奇类型的号码数量最多，因此，该类型的号码最容易开出来。在我们使用最大奇数连续数量这一技术指标进行分析时，如果我们判断出当期最高出2连奇，那就能把目标缩小到312500注以内。
接着，我们对这两个连续的奇数进行定位。2连奇的号码按2连奇号码所处的位置进行分类，其数量分布如下表所示：
2连奇所处的位置 | 号码数量 | 所占比例（%） | 理论周期（注） |
第1位，第2位 | 109375 | 30.43 | 3.28 |
第2位，第3位 | 62500 | 17.39 | 5.75 |
第3位，第4位 | 62500 | 17.39 | 5.75 |
第4位，第5位 | 62500 | 17.39 | 5.75 |
第5位，第6位 | 109375 | 30.43 | 3.28 |
（注：上表中的理论周期是指该类型的号码在2连奇这个小样本中的理论周期，也就是在2连奇共359375注号码中，理论上多少期出一次，并不是指该类型的号码在全部一百万注号码中的理论周期，那样的话，该类型号码的周期将要比表中大的多。）
我们根据上表中各位置形态所占的比例，以及该位置形态的历史走势，可以对2连奇所处的位置进行定位。比如说：2连奇出在第一位，第二位。那么第一位、第二位、第三位的号码范围分别就是：
第一位：13579；第二位：13579；第三位：02468；
接下来，我们再用其它方法，比如说，012路形态，位和形态，位差形态，对第四位，第五位，第六位上的号码进行进一步的定位。
我们可以运用同样的方法，从偶数、质数、合数、大数、小数的角度出发，进行技术分析。
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